Answer:
The answer is: 6.6150 × 10⁴ kJ
Step-by-step explanation:
Given reaction: C₂H₄ (ethene) + H₂ → C₂H₆ (ethane)
Given: Heat of hydrogenation of ethene = 135 kJ/mol
given mass of ethane = 14.7 kg = 14700 g (∵ 1 kg = 1000g)
Molar mass of ethane = 30 g/mol
The number of moles of ethane = given mass ÷ molar mass = 14700 g ÷ 30 g/mol = 490 moles
As 1 mole ethene gives 1 mole ethane on hydrogenation.
Therefore, number of moles of ethane = number of moles of ethene = 490 moles
Therefore, the heat of hydrogenation for the formation of 490 moles (14.7 kg) ethane = 490 mol × 135 kJ/mol = 66150 kJ = 6.6150 × 10⁴ kJ