Answer:
The correct option is: Oxygen
Step-by-step explanation:
According to the Ideal Gas Equation: P.V = n. R.T
Here, R - ideal gas constant, P - absolute pressure, V - volume, T - temperature, n - number of moles of gas.
Also, n = given mass of gas (w) ÷ molar mass of gas (M)
Given: P = gauge pressure + barometric pressure = 1 atm + 1 atm = 2 atm; V = 5 L; w = 13 g; R = 0.08206 L·atm·mol⁻¹·K⁻¹; T = 27 °C = 27°C + 273.15 = 300.15K (∵ 0°C = 273.15 K).
Since, P.V = n. R.T = (w ÷ M) . R.T
⇒ M = (w. R.T) ÷ (P.V) = (13g × 0.08206 L·atm·mol⁻¹·K⁻¹ × 300.15K)÷(2atm × 5 L)
⇒ M = 32 g.mol⁻¹
As we know, the molar mass of oxygen gas (O₂) is 32 g.mol⁻¹.
Therefore, the gas is oxygen.