Question

what was the initial temperature is 250 calories reply .1 kg of gold the final temperature of the gold was 175°c ? the specific heat cold is 0.175 °c​

Answer 1

`115.2^(\circ)C`

Step-by-step explanation:

When an amount of energy Q is supplied to a substance of mass m, the temperature of the substance increases by
`\Delta T`, according to the equation

`Q=mC_s \Delta T`

where
`C_s` is the specific heat capacity of the substance.

In this problem, we have:

`Q=250 \cdot 4.184 =1046 J` is the amount of heat supplied to the sample of gold

m = 0.1 kg = 100 g is the mass of the sample

`C_s = 0.175 J/gC` is the specific heat capacity of gold

Solving for
`\Delta T`, we find the change in temperature

`\Delta T = (Q)/(m C_s)=(1046)/((100)(0.175))=59.8^(\circ)`

And since the final temperature was

`T_f = 175^(\circ)`

The initial temperature was

`T_i = T_f - \Delta T= 175 -59.8=115.2^(\circ)C`