Question

The scale is set by Fs = 160.0 N. We release the block at x = 12 cm. How much work does the spring do on the block when the block moves from xi = +8.0 cm to (a) x = +5.0 cm, (b) x = −5.0 cm, (c) x = −8.0 cm, and (d) x = −10.0 cm?

Answer 1

Answer:a)480Nm b)2080Nm c)2560Nm d)2880Nm

Explanation:

Work is said to be done when a force is applied to move an object through a particular distance.

Workdone=Force×distance

Force=160.0N

a) when a block moves from +8cm distance to +5cm, the total distance covered will be 3cm

Workdone=160×3 = 480Nm

b)when a block moves from +8cm distance to -5cm, the total distance covered will be +13cm

Workdone=160×13 = 2080Nm

c)when a block moves from +8cm distance to -8cm, the total distance covered will be +16cm

Workdone=160×16 = 2560Nm

d)when a block moves from +8cm distance to -10cm, the total distance covered will be +18cm

Workdone=160×18 = 2880Nm