189k views
0 votes
The scale is set by Fs = 160.0 N. We release the block at x = 12 cm. How much work does the spring do on the block when the block moves from xi = +8.0 cm to (a) x = +5.0 cm, (b) x = −5.0 cm, (c) x = −8.0 cm, and (d) x = −10.0 cm?

User Ddyer
by
7.7k points

1 Answer

4 votes

Answer:a)480Nm b)2080Nm c)2560Nm d)2880Nm

Explanation:

Work is said to be done when a force is applied to move an object through a particular distance.

Workdone=Force×distance

Force=160.0N

a) when a block moves from +8cm distance to +5cm, the total distance covered will be 3cm

Workdone=160×3 = 480Nm

b)when a block moves from +8cm distance to -5cm, the total distance covered will be +13cm

Workdone=160×13 = 2080Nm

c)when a block moves from +8cm distance to -8cm, the total distance covered will be +16cm

Workdone=160×16 = 2560Nm

d)when a block moves from +8cm distance to -10cm, the total distance covered will be +18cm

Workdone=160×18 = 2880Nm

User Malat
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories