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What are (a) the charge and (b) the charge density on the surface of a conducting sphere of radius r whose potential is V (with V = 0 at infinity)? State your answers in terms of the given variables, using ε0 if necessary.

1 Answer

7 votes

Answer:

Part a)


Q = 4\pi \epsilon_0 r V

Part b)


\sigma = (\epsilon_0 V)/(r)

Step-by-step explanation:

Part a)

As we know that potential of the sphere is given as


V = (kQ)/(r)


V = (Q)/(4\pi \epsilon_0 r)

now we have


Q = 4\pi \epsilon_0 r V

Part b)

Now we know that for conducting charged sphere whole charge is distributed over the surface of the sphere

so we will have


\sigma = (Q)/(4\pi r^2)

now we have


\sigma = (4\pi \epsilon_0 r V)/(4\pi r^2)


\sigma = (\epsilon_0 V)/(r)

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