Answer:
Q= 231.88 W/m²
Step-by-step explanation:
Given that
L= 20 cm
K= 2.79 W/m·K
T₁=50°C
T₂= 22°C
h=15 W/m₂·K
The total thermal resistance
![R=(L)/(KA)+(1)/(hA)](https://img.qammunity.org/2020/formulas/engineering/college/lv963c359zs5qtgpu1f6npmnlicfppiw91.png)
Now by putting the values
![R=(L)/(KA)+(1)/(hA)](https://img.qammunity.org/2020/formulas/engineering/college/lv963c359zs5qtgpu1f6npmnlicfppiw91.png)
![R=(0.2)/(2.79A)+(1)/(15A)](https://img.qammunity.org/2020/formulas/physics/college/zy3dmr7snmc907xrzvn6vd6pv0af66bi24.png)
R= 0.138 K/W ( for heat flux A= 1 m²)
Heat flux Q= ΔT/R
Q= (50-22)/0.138 = 32/0.138 W
Q= 231.88 W/m²