Question

What is the equation of the line that passes through the points (-1, 3) and (1, 11)

Answer 1

To find the slope of this line, you would use the formula

y2 - y1/ x2 - x1

11 - 3 / 1 - (-1)=

8/2

4

The slope of your line would be 4

Explanation:

Answer 2

Equation of line passing through (-1 , 3) and ( 1 , 11 ) is y - 3= 4x + 4

Solution:

Need to determine equation of line passing through points ( -1 , 3 ) and ( 1 ,11 ) Equation of line passing through point
`\left(x_(1), y_(1)\right) \text { and }\left(x_(2), y_(2)\right)` is given by

`y-y_(1)=(\left(y_(2)-y_(1)\right))/(\left(x_(2)-x_(1)\right))\left(x-x_(1)\right)` ---- equation 1

`\text { Here } x_(1)=-1, y_(1)=3, x_(2)=1, y_(2)=11`

Substituting given value in (1) we get

`\begin{array}{l}{y-3=((11-3))/((1-(-1)))(x-(-1))} \\\\ {=>y-3=(8)/(2)(x+1)} \\\\ {=>y-3=4(x+1)} \\\\ {=>y-3=4 x+4}\end{array}`

Hence equation of line passing through (-1 , 3) and ( 1 , 11 ) is y - 3 = 4x + 4