Question

Compressed air is used to fire a 50 gram ball vertically from a 1-meter tube. The air exerts an upward force of 2 N on the ball as long as it in the tube. How high does the ball go above the top of the tube?

Answer 1

The reached by the ball above the top of the tube is 4.08 m.

How to calculate the height reached by the ball?

The reached by the ball above the top of the tube is calculated as follows;

The compressed air will be treated as a compressed spring and the force constant of the air is calculated as follows;

k = F/L

k = (mg) / L

where;

• mass of the ball
• L is the length of the tube

k = (005 kg x 9.8 m/s² ) / 1 m

k = 0.49 N/m

The distance reached by the ball when the air exerts upward force of 2 N is calculated as;

F = kx

x = F / k

x = 2 N / 0.49 N/m

x = 4.08 m

Answer 2

Height, h = 4.08 meters

Step-by-step explanation:

It is given that,

Mass of the ball, m = 50 gram = 0.05 kg

Length of the tube, l = 1 m

Applied force to the ball, F = 2 N

We need to find the the height reached by the ball above the top of the tube. It can be calculated using work energy theorem as :

`F.l=mgh`

`h=(Fl)/(mg)`

`h=(2* 1)/(0.05* 9.8)`

h = 4.08 meters

So, the the height reached by the ball above the top of the tube is 4.08 meters. Hence, this is the required solution.