Question

In a circus performance, a monkey is strapped to a sled and both are given an initial speed of 5.0 m/s up a 25.0° inclined track. The combined mass of monkey and sled is 18 kg, and the coefficient of kinetic friction between sled and incline is 0.20. How far up the incline do the monkey and sled move?

Answer 1

Answer:3.01 m

Step-by-step explanation:

Given

initial speed
`(v_i)=5 m/s`

inclination
`=25^(\circ)`

mass of monkey and Sledge=18 kg

coefficient of kinetic Friction
`\mu_k=0.2`

Work done=Change in kinetic Energy+Change in Potential Energy

`W.D.=\mu _k mg\cos \theta`(angle between force and displacement is 180)

`W.D.=0.2* 18* 9.8* s* \cos (180)`

`0.2* 18* 9.8* s* \cos (180)=(k.E._f-K.E._i)+(P.E._f-P.E._i)`

`0.2* 18* 9.8* s* \cos (180)=0-(mv_i^2)/(2)+mgs\sin 25`

`-s(0.2* 18* 9.8+mg\sin 25)=-(mv_i^2)/(2)`

s=3.01 m