Question

What is the internal energy of 3.00 mol of Nz gas at 25°C?

Answer 1

`1.86\cdot 10^4 J`

Step-by-step explanation:

I assume you mean
`N_2`, which is a diatomic gas.

For a diatomic gas, the internal energy is given by

`U=(5)/(2)nRT`

where

n is the number of moles

R is the gas constant

T is the absolute temperature

Here we have:

n = 3.00 mol

`R=8.314 J/(mol K)`

`T=25^(\circ) +273=298 K`

Substituting into the equation, we find the gas internal energy:

`U=(5)/(2)(3.00)(8.314)(298)=1.86\cdot 10^4 J`