Answer:
It decreases by a factor of 4
Step-by-step explanation:
The gravitational force between two masses is given by
![F=(Gm_1 m_2)/(r^2)](https://img.qammunity.org/2020/formulas/physics/high-school/zipb47luow89tvt4at2swtc7m6a7hrx1lo.png)
where
G is the gravitational constant
m1, m2 are the two masses
r is the separation between the two masses
In this problem, the distance between the masses is doubled, so
r' = 2r
Substituting into the equation, we see that the new force is
![F'=(Gm_1 m_2)/((2r)^2)=(1)/(4)(Gm_1m_2)/(r^2))(F)/(4)](https://img.qammunity.org/2020/formulas/physics/middle-school/3e4z8gs3kia3t841zb4354tsiza8e7s630.png)
So, the force decreases by a factor of 4.