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Segments proofs. B is the midpoint of AC Prove 2bc=AB

Segments proofs. B is the midpoint of AC Prove 2bc=AB-example-1
User Palotasb
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In the context of B being the midpoint of AC, the proof demonstrates that
\(2 \cdot BC\) equals AB, highlighting the relationship between the segments in a scenario where B is the midpoint.

In the given scenario where B is the midpoint of AC, we aim to prove that
\(2 \cdot BC = AB\).

By the definition of a midpoint, BC is equal to BA (segment addition postulate).

Now, considering the entire segment AC, which is composed of two equal parts (AB and BC), we can express AC as
\(2 \cdot BC\).

Substituting the earlier established equality BC = BA into this expression, we get
\(2 \cdot BA\), which is equivalent to AB.

Thus,
\(2 \cdot BC = AB\), confirming the assertion that in a segment where B is the midpoint, the double of one of its segments equals the other segment.

User Zhangyangyu
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Answer:

B is the midpoint of AC because <AB and <BC have the same measurement.

User Ankit Balyan
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