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Solve by completing the square w^2-10w+21=0

1 Answer

6 votes

Answer:

The solutions are w=7, w=3

Explanation:

we have


w^2-10w+21=0

Group terms that contain the same variable and move the constant term to the right side


w^2-10w=-21

Complete the square


w^2-10w+5^2=-21+5^2


w^2-10w+25=-21+25


w^2-10w+25=4

Rewrite as perfect squares


(w-5)^2=4

take square root both sides


w-5=(+/-)2


w=5(+/-)2


w_1=5(+)2=7


w_2=5(-)2=3

therefore

The solutions are w=7, w=3

User Boardy
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