58.1k views
2 votes
Helppp please.I don’t know how to graph it.Please help letter C.

Helppp please.I don’t know how to graph it.Please help letter C.-example-1
User Ameera
by
8.6k points

1 Answer

7 votes

Your equation for A is correct.

Part B

To find the x-intercepts, let y = 0 in the equation shown in part A and solve for x.

To find the y-intercept, let x = 0 in the equation shown in part A and solve for y.

So, do the math.

45x + 30y = 1350

Let x = 0

45(0) + 30y = 1350

30y = 1350

y = 1350/30

y = 45

The y-intercept is the point (0, 45).

Let y = 0

45x + 30(0) = 1350

45x = 1350

x = 1350/45

x = 30

The x-intercept is the point (30, 0).

The x-intercept represents where the graph crosses the x-axis and the y-intercept represents where the graph crosses the y-axis.

Part C

To graph this linear equation, plot the x and y intercepts on the xy-plane given and connect the points with a straight line.

Look: plot the points (30, 0) and (0, 45) and connect the points with a straight line. This will yield the graph of the linear equation shown in Part A.

User Adam Pery
by
9.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories