Question

(x-3y+ 3z=-4

2x+3y-z =15

(4x-3y- z=19

- What is the solution to the system?

Answer 1

Answer: x=5,y=1 and z=-2

5,1,-2

Explanation:

Answer 2

x=5,y=1 and z=-2

Explanation:

We are given that system of equation

`x-3y+3z=-4` (I equation)

`2x+3y-z=15` (II equation )

`4x-3y-z=19` (III equation )

Equation II multiply by 3 then add with equation I

Then, we get

`7x+6y=41` ....(Equation IV)

Subtract equation II from equation III then we get

`2x-6y=4` (equation V)

Adding equation IV and equation V then, we get

`9x=45`

`x=5`

Substitute x=5 in equation V then, we get

`2(5)-6y=4`

`10-6y=4`

`6y=10-4=6`

`y=1`

Substitute x=5 and y=1 in equation then, we get

`5-3(1)+3z=-4`

`2+3z=-4`

`3z=-4-2=-6`

`z=(-6)/(3)=-2`

Hence, the solution for the given system of equation is given by

x=5,y=1 and z=-2