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What are the solutions of 2x2 + 3x = −5?

the quantity negative 3 plus or minus i square root of 31 all over 4

the quantity negative 3 plus or minus 7i all over 4

the quantity negative 3 plus or minus i square root of 19 all over 4

the quantity negative 3 plus or minus 4i all over 4

1 Answer

5 votes

Answer:a

Explanation:

Given


2x^2+3x=-5

or it can be write as


2x^2+3x+5=0

Finding discriminant of equation


D=b^2-4ac


D=3^2-4* 2* 5

D=9-40=-31

D<0 therefore there are no real roots

so


x=(-3\pm √(3^2-4* 2* 5))/(2* 2)


x=(-3+i√(31))/(4) and (-3 -i√(31))/(4)

User Diego Segura
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