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Can some help me with this algebra problem. I have done it several times but it seems to be wrong everytime

Can some help me with this algebra problem. I have done it several times but it seems-example-1
User MRu
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1 Answer

5 votes

Answer:

x=25.61

Explanation:

To determine the smallest amount, in dollars , that you can charge and make a profit of atleast $415, you need to find the value of x that gives p=415.

Substitute p=415 in the given quadratic equation and solve it for x.


415=-0.5x^(2) +36x-179


x^(2) -72x+1188=0


x=\frac{-(-72)+\sqrt{(-72)^(2)-4(1)(1188)} }{2(1)}

on solving we get
x=25.61

The smallest amount you could charge and make a profit of $415 is $25.61

User Joel Vroom
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