Question

The first and second coils have the same length, and the third and fourth coils have the same length. They differ only in the cross-sectional area. According to theory, what should be the ratio of the resistance of the second coil to the first and the fourth coil to the third? Calculate these ratios for your experimental results and compare the agreement with the expected ratio.

Answer 1

`(R_2)/(R_1)=(A_1)/(A_2)\\(R_4)/(R_3)=(A_3)/(A_4)`

Step-by-step explanation:

The resistance of a conductor is directly proportional to its length and is inversely proportional to its cross-sectional area, this dependence is given by:

`R=(\rho L)/(A)`

`\rho` is the material's resistance, L is the legth and A is the cross-sectional area.

For the first and second coils, we have:

`R_1=(\rho L)/(A_1)\\R_2=(\rho L)/(A_2)\\\rho L=R_1A_1\\\rho L=R_2A_2\\R_1A_1=R_2A_2\\(R_2)/(R_1)=(A_1)/(A_2)`

For the third and fourth coils, we have:

`R_3=(\rho L')/(A_3)\\R_4=(\rho L')/(A_4)\\\rho L'=R_3A_3\\\rho L'=R_4A_4\\R_3A_3=R_4A_4\\(R_4)/(R_3)=(A_3)/(A_4)`