Question

A coffee mixture contains beans that sell for $0.08 per pound and $0.32 per pound. If 110 pounds of beans create a mixture that sells for $0.27 per pound, to the nearest tenth of a pound, how much of each bean is used in the mixture?

Answer 1

B = 87.08 pounds @ $0.32

A = 22.92 pounds @ $0.08

Explanation:

given,

cost of beans (A)= $ 0.08/pound

and another beans cost (B) = $ 0.32 /pound

total weight of the pound = 110 pound

selling price of mixture = $ 0.27/pound

cost of each bean = ?

A + B = 110

A = 110 - B-------(1)

0.08 A + 0.32 B = 0.27 x 110

0.08 A + 0.32 B = 29.7

Putting value of A

0.08(110 - B) + 0.32 B = 29.7

8.8 - 0.08 B + 0.32 B = 29.7

0.24 B = 20.9

B = 87.08 pounds @ $0.32

A = 22.92 pounds @ $0.08