Answer:
speed greater than 0.08 mi/min
Explanation:
given data
distance = 2 mi
time = 25 min
to find out
the distance you travel and your speed and time related
solution
we know that distance is
distance = speed × time ...............1
so at park at most 25 min
so we need time =
![(distanec)/(speed) \leq 25](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bzgc039lmw15014gtm0iso1rxy35bk6six.png)
so here
we know
![(2)/(25) \leq speed](https://img.qammunity.org/2020/formulas/mathematics/middle-school/23qll7tw3ks0z8yalrtf3lnpviuh3w6sy0.png)
so
![0.08 \leq speed](https://img.qammunity.org/2020/formulas/mathematics/middle-school/u9n8kof1ka2wdpx0czpfc3s3mux3rrzabt.png)
so we can say that he need to run at speed greater than 0.08 mi/min