Question

A submarine reaches the depth of 105 m (densi-

ty of sea water = 1030 kg/m

).
Calculate the absolute pressure that the subma-
rine need to be able to withstand.​

Answer 1

The pressure the the submarine need to able to withstand is

P=1.161195 Mpa

P=1.161195
`x10^(6)` pa

Step-by-step explanation:

`Pressure= (Density_(object) *Gravity*Depth_(object) )+Pressure_(atmosphere)\\Pressure_(atmosphere)=101325 pa \\\\P=(1030 (kg)/(m^(3))*9.8(m)/(s^(2) )*105m)+ 101325 pa\\P=(1059870 (kg*m^(2) )/(m^(3)*s^(2)))+101325 pa\\P=(1059870 (N)/(m^(2))+101325 pa\\ P=1059870 pa +101325 pa=1161195pa\\P=1.161x10^(6)pa\\ P=1.161Mpa`