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A human resources representative claims that the proportion of employees earning more than $50,000 is less than 40%. To test this claim, a random sample of 700 employees is taken and 305 employees are determined to earn more than $50,000. The following is the setup for this hypothesis test: {H0:p=0.40Ha:p<0.40 Find the test statistic for this hypothesis test for a proportion. Round your answer to 2 decimal places. Provide your answer below:

2 Answers

4 votes

Answer: 0.973

Explanation:

Here are the steps needed to calculate the p-value for a hypothesis test for a proportion:

Determine if the hypothesis test is left tailed, right tailed, or two tailed.

Compute the value of the test statistic.

If the hypothesis test is left tailed, the p-value will be the area under the standard normal curve to the left of the test statistic z0

If the test is right tailed, the p-value will be the area under the standard normal curve to the right of the test statistic z0

If the test is two tailed, the p-value will be the area to the left of −|z0| plus the area to the right of |z0| under the standard normal curve

For this example, the test is a left tailed test.

For this hypothesis test, the proportion of successes is p^=305700≈0.4357.

The test statistic is calculated as follows:

z=p^−p0p0⋅(1−p0)n√

z=0.4357−0.400.40⋅(1−0.40)700√

z≈1.93

The value of the test statistic is 1.93.

Thus the p-value is the area under the Standard Normal curve to the left of a z-score of 1.93.

z 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09

1.5 0.933 0.934 0.936 0.937 0.938 0.939 0.941 0.942 0.943 0.944

1.6 0.945 0.946 0.947 0.948 0.949 0.951 0.952 0.953 0.954 0.954

1.7 0.955 0.956 0.957 0.958 0.959 0.960 0.961 0.962 0.962 0.963

1.8 0.964 0.965 0.966 0.966 0.967 0.968 0.969 0.969 0.970 0.971

1.9 0.971 0.972 0.973 0.973 0.974 0.974 0.975 0.976 0.976 0.977

2.0 0.977 0.978 0.978 0.979 0.979 0.980 0.980 0.981 0.981 0.982

From a lookup table of the area under the Standard Normal curve, the corresponding area is then 0.973.

User Thorin
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7.4k points
4 votes

Answer: z(p) = 1.9286 and we reject H₀

Explanation:

1) According to problem ststement : We need to solve an Hypotesis test proportion so:

H₀ P₀ = 0,4 and Hₐ < 0,4 ( Alternative hipotesis)

From 700 employes 305 are determined to earn more than $ 50000

Proportion pₐ = 305/700 = 0,4357 pₐ = 0,4357

proportions are p = 0.4 and q = 0,6

We will asume a confidence level of 95 % hence α= 1-0,95 α = 0,05

so from z table we find z(c) = 1,64

Therefore we must calculate our z(p) = ( pₐ-p₀) ÷√(p*q)/n

Calculating z(p) = 0,0357 /0,01851 ⇒ z(p) 1.9286

Our test is one of the form Hₐ < ; that means is a right tail test, and the value z(p) is bigger than our critical value (z(c) = 1.64) so we rejecte H₀

User Mishigen
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6.3k points