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Question in picture below

Question in picture below-example-1
User Andrew Nepogoda
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1 Answer

17 votes
17 votes

Answer: f(x)=(x-7)(x-4) for x<=4 or x>=7

f(x)=-(x-7)(x-4) for 4<x<7

Explanation:

|x^2-11x+28|=

|x^2-4x-7x+28|=

|x(x-4)-7(x-4)|=|(x-7)(x-4)|

f(x)=(x-7)(x-4) for x-4<=0 or x-7>=0 ==> both x-4 and x-7 have to be negative/positive in order for f(x) to be positive.

f(x)=-(x-7)(x-4) for x-4>0 and x-7<0 ==> Only x-4 or x-7 have to be positive in oder for f(x) to be positive.

f(x)=(x-7)(x-4) for x<=4 or x>=7

f(x)=-(x-7)(x-4) for x>4 and x<7

f(x)=(x-7)(x-4) for x<=4 or x>=7

f(x)=-(x-7)(x-4) for 4<x<7

User Rleelr
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