Question

a hammer drops from a height of 8 meters. calculate the speed with which it hits the ground. show work

Answer 1

12.5 m/s

Step-by-step explanation:

The motion of the hammer is a free fall motion, so a uniformly accelerated motion, therefore we can use the following suvat equation:

`v^2-u^2=2as`

Where, taking downward as positive direction, we have:

s = 8 m is the displacement of the hammer

u = 0 is the initial velocity (it is dropped from rest)

v is the final velocity

`a=g=9.8 m/s^2` is the acceleration of gravity

Solving the equation for v, we find the final velocity:

`v=√(u^2+2as)=√(0+2(9.8)(8))=12.5 m/s`

So, the final speed is 12.5 m/s.