Question

A car accelerates from 21.0 m/s to 46.0 m/s in 2.5 seconds. What is the acceleration of the car.

Answer 1

`10.0 m/s^2`

Step-by-step explanation:

The acceleration of an object is given by

`a=(v-u)/(t)`

where

v is the final velocity

u is the initial velocity

t is the time interval it takes for the velocity to change from u to v

For the car in this problem,

u = 21.0 m/s

v = 46.0 m/s

t = 2.5 s

Substituting, we find the acceleration

`a=(46.0-21.0)/(2.5)=10.0 m/s^2`