For this case we must solve the following system of equations:
![5x-2y = -6\\3x-4y = -26](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fjo9xel25a105xz5keozhdtvrsze80abcd.png)
We multiply the first equation by -2:
![-10x + 4y = 12](https://img.qammunity.org/2020/formulas/mathematics/middle-school/h64ixmmyjmnbt2yilyz86i3ptvzjs4cqld.png)
We add the new equation with the second one:
![-10x + 3x + 4y-4y = 12-26](https://img.qammunity.org/2020/formulas/mathematics/middle-school/feveala10eck4gqesez85ja14zv5k0b0fk.png)
We have different signs subtracted and the sign of the major is placed:
![-7x = -14\\x = \frac {-14} {- 7}\\x = 2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hv2je5mpi5jo2kouup1bw3b4mtftliondi.png)
Now we find the value of the variable "y":
![3x-4y = -26\\3 (2) -4y = -26\\6-4y = -26\\-4y = -26-6\\-4y = -32\\y = \frac {-32} {- 4}\\y = 8](https://img.qammunity.org/2020/formulas/mathematics/middle-school/i17a1b5k23zzgfqpiv92v121lp2xqdep7z.png)
Thus, the solution of the system is given by:
![(x, y) :( 2,8)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2l8vv9nprcz6zu6w4kig111fvk8iut7bnv.png)
Answer:
![(x, y) :( 2,8)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2l8vv9nprcz6zu6w4kig111fvk8iut7bnv.png)