Answer:
The line that passes through (-5,2) and is perpendicular to y+3=2x is

Solution:
Given, line equation is y + 3 = 2x ⇒ 2x – y – 3 = 0
We have to find a line that is perpendicular to y + 3 = 2x and passing through (-5, 2).
Now, let us find the slope of the given line,

We know that, slope of a line
slope of perpendicular line = -1
Then, 2
slope of perpendicular line = -1

Now, slope of our required line =
and it passes through (-5, 2)
We know that, point slope form is

Here in our problem,

Then, line equation

2(y – 2) = -1(x + 5)
2y – 4 = -x – 5
x + 2y + 5 – 4 = 0

Thus the point slope form is
