Answer:
4374 km/h
Step-by-step explanation:
The momentum of the 1500 kg object is given by:
![p = mv](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wxdsy4acya1edya0b1jbgaey6t0bq88zq1.png)
where
m = 1500 kg is the mass
v = 1.62 m/s is the velocity
Substituting,
![p=(1500)(1.62)=2430 kg m/s](https://img.qammunity.org/2020/formulas/physics/middle-school/lf4lnbqb3pxzdnlr79g0ifvqap4ivfyzst.png)
We know that the smaller object of mass m' = 2 kg has the same momentum, so we can find its velocity by re-arranging the same equation:
![v' = (p)/(m')=(2430)/(2)=1215 m/s](https://img.qammunity.org/2020/formulas/physics/middle-school/v3pv5fwlz8m0i3d4mnypvuvy6e8u8s69pg.png)
Now to convert into km/h, keep in mind that:
1 km = 1000 m
1 h = 3600 s
So, we find
![v' = 1215 m/s \cdot (3600 s/h)/(1000 m/km)=4374 km/h](https://img.qammunity.org/2020/formulas/physics/middle-school/2a6va1xpju0cbb6qktyr4yqwqie0nl1cgo.png)