Answer:
Yes, the graph of the function has vertical asymptote at x=-1.
Explanation:
Given : Function
![f(x)=(x^2-8x-9)/(x+1)](https://img.qammunity.org/2020/formulas/mathematics/high-school/4pe672eiverxefw72rkoo3f8mbqkm3z8ic.png)
To find : Does the graph of the function have a vertical asymptote or a point missing at x = −1?
Solution :
The vertical asymptote of the rational function is when we put denominator equals to zero.
In the function
Denominator -
![x+1](https://img.qammunity.org/2020/formulas/mathematics/high-school/l5ra222ymml3wllfcdt4f6uz03hx7d11c9.png)
Vertical asymptote is at
![x+1=0\Rightarrow x=-1](https://img.qammunity.org/2020/formulas/mathematics/college/htv8l5e2hbvrsv5t8oqmys1wllkhbizwo2.png)
Yes, the graph of the function has vertical asymptote at x=-1.