Question

A skater starts skating from rest and speeds up to 6m/s^2 in 12 seconds. What is the acceleration of the skater?

Answer 1

2m/s^2

Step-by-step explanation:

Answer 2

`0.5 m/s^2`

Step-by-step explanation:

The acceleration of an object is given by the equation

`a=(v-u)/(t)`

where

v is the final velocity of the object

u is the initial velocity

t is the time taken for the velocity to change from u to v

For the skater in this problem we have:

u = 0 (assuming it starts from rest)

v = 6 m/s is the final velocity of the skater

t = 12 s is the time taken

Substituting, we find

`a=(6-0)/(12)=0.5 m/s^2`