Question

What is y=x^4/x^3 when values of x= {-2, 0, 3, 5, 7}

Answer 1

For this case we have a function of the form
`y = f (x)` where:

`f (x) = \frac {x ^ 4} {x ^ 3}`

We simplify eliminating common terms of the numerator and denominator:

`f (x) = x`

We must find the values of the function when:

x = {-2, 0, 3, 5, 7}

So, we have:

For
`x = -2`:

`f (-2) = - 2`

For
`x = 0`

`f (0) = 0`

For
`x = 3`

`f (3) = 3`

For
`x = 5`

`f (5) = 5`

For
`x = 7`:

`f (7) = 7`

Thus, the values of the function are:

y = {-2, 0, 3, 5, 7}

Answer:

y = {-2, 0, 3, 5, 7}