Answer: The answer is: 1/4 of the progeny would have long wings and normal bristles if there is no recombination.
Explanation: If you cross a heterozygous wild type (VvRr) with an homozygous recessive (vvrr) you obtain.
According to segregation law: Gametes 1/2 V, 1/2 v, v
1/2 R, 1/2 r x r
After dfistribution you end up with 1/4 VvRr, 1/4vvRr, 1/4 vvRr, 1/4 vvrr
from this result only 1/4 th ends up with wild type.