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1. Identify whether the functions shown are rational:

a. f(x) = x / x^2 + 1
b. f(x) = √x / x^2 + 1
c. f(x) = x / x^0.4 + 1
d. f(x) = (x / x^2 + 1)^2
e. f(x) = √2x / ex^2 + √3

User Funcraft
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1 Answer

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Answer:

a) Rational function

b) Not a rational function

c) Not a rational function

d) Rational function

e) Not a rational function

Explanation:

A rational function is of the form;


f(x)=(p(x))/(q(x)) ,\:q(x)\\e 0 where
p(x) and
q(x) are polynomial functions.

For option a)
f(x)=(x)/(x^2+1), we have both the numerator
p(x)=x and the denominator
q(x)=x^2+1 are polynomial functions, hence
f(x)=(x)/(x^2+1) is a rational function.

For option b)
f(x)=(√(x))/(x^2+1),
p(x)=√(x) is not a polynomial function hence
f(x)=(√(x))/(x^2+1) is not a rational function.

For option c) we have
f(x)=(x)/(x^(0.4)+1),
q(x)=x^(0.4)+1 is not a polynomial function hence
f(x)=(x)/(x^(0.4)+1) is not a rational function.

For option d)
f(x)=((x)/(x^2+1))^2 =(x^2)/(x^4+2x^2+1) both
p(x)=x^2 and
q(x)=x^4+2x^2+1 are polynomials hence
f(x)=((x)/(x^2+1))^2 is a rational function.

For option e)
f(x)=(√(2x) )/(e^(x^2)+√(3) ) both the numerator and the denominator are not polynomials hence
f(x)=(√(2x) )/(e^(x^2)+√(3) ) is not a rational function.

User Npk
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