Question

10) A balloon was filled to 1.25 Lat 25.2°C. 0.235 g of helium was used to fill it. What is the pressure?

R = 0.08206 L.atm/°C-mole.

Answer 1

P = 0.1 atm

Step-by-step explanation:

Given data:

Volume = 1.25 L

Temperature = 25.2 °C

Mass of gas = 0.235 g

R = 0.08206 L. atm/°C. mol

Pressure = ?

Solution:

first of all we will calculate the number of moles.

Number of moles = mass / molar mass

Number of moles = 0.235 g/ 4g/mol

Number of moles = 0.06 mole

For pressure:

PV = nRT

P = nRT / V

P = 0.06 mol × 0.08206 L. atm/°C. mol × 25.2°C / 1.25 L

P = 0.124 L. atm / 1.25 L

P = 0.1 atm