One x-intercept for a parabola is at the point (0.6,0). Use the quadratic formula to find the other x-intercept for the parabola defined by this equation: y=-5x^2 + 8x - 3

Question

asked Jul 17, 2020 30.2k views

2 Answers

FryHard · Answer 1 · 2020-07-22T12:53:15+0000

The other x-intercept for the parabola y = -5x² + 8x - 3 is (1, 0)

How to determine the other x-intercept for the parabola

From the question, we have the following parameters that can be used in our computation:

y = -5x² + 8x - 3

The quadratic formula is represented as

$x = (-b \pm √(b^2 - 4ac))/(2a)$

Where

a = -5

b = 8

c = -3

Substitute the known values into the equation

$x = (-8 \pm √((-8)^2 - 4 * -5 * -3))/(2 * -5)$

This gives

$x = (-8 \pm √(4))/(-10)$

So, we have

$x = (-8 \pm 2)/(-10)$

Expand and evaluate

x = (-8 + 2)/(-10) and x = (-8 - 2)/(-10)

This gives

x = 0.6 and x = 1

Hence, the other x-intercept for the parabola is (1, 0)