Question

One x-intercept for a parabola is at the point (0.6,0). Use the quadratic formula to find the

other x-intercept for the parabola defined by this equation:
y=-5x^2 + 8x - 3

Answer 1

the other x intercept would be -0.6

Explanation:

Answer 2

The other x-intercept for the parabola y = -5x² + 8x - 3 is (1, 0)

How to determine the other x-intercept for the parabola

From the question, we have the following parameters that can be used in our computation:

y = -5x² + 8x - 3

The quadratic formula is represented as

`x = (-b \pm √(b^2 - 4ac))/(2a)`

Where

a = -5

b = 8

c = -3

Substitute the known values into the equation

`x = (-8 \pm √((-8)^2 - 4 * -5 * -3))/(2 * -5)`

This gives

`x = (-8 \pm √(4))/(-10)`

So, we have

`x = (-8 \pm 2)/(-10)`

Expand and evaluate

x = (-8 + 2)/(-10) and x = (-8 - 2)/(-10)

This gives

x = 0.6 and x = 1

Hence, the other x-intercept for the parabola is (1, 0)