Answer:
Bill has bags of candy with five pieces in each. The Bill has 16 bags
Solution:
Given, Dan has bags of candy with two pieces in each.
Bill has bags of candy with five pieces in each.
Bill has six more bags than Dan.
Then, number of bags with bill = 6 + number of bags with dan.
The total number of pieces candy the two boys have 100.
Now, candies with bill + candies with dan = 100
⇒ 5 pieces per bag x number of bags with bill + 2 pieces per bag x number of bags with dan = 100
⇒ 5 x (6 + number of bags with dan) + 2 x number of bags with dan = 100
⇒ 30 + 5 x number of bags with dan + 2 x number of bags with dan = 100
⇒ (5 + 2) x number of bags with dan = 100 – 30
⇒ 7 x number of bags with dan = 70
⇒ Number of bags with dan = 10
So, number of bags with bill = 6 + 10 = 16
Hence, bill has 16 bags.