Answer:
Explanation:
from equ. of a straight line
y=mx+c
put x=-4 , y=-2 (first row)
-2=-4m+c
-4m+c=-2 ------- 1
put x=2, y=4 (forth row)
4=2m+c
2m+c=4 -------- 2
solving equ 1 and 2 simultaneously
-4m+c=-2
-
2m+c=4
2m-(-4m) +(c-c)=4-(-2)
6m=6
m=1
put m in equ. 2
2(1)+c=4
c=4-2
c=2.
from y=mx+c
y=(1)x+2
y=x+2
A is the correct option