Answer:
(a) 68%
(b)54.6 kW
Step-by-step explanation:
(a) This would be solved by using the equation for a Carnot Engine.
e = 1 - Tc/Th
Th = the higher temperature (1870)
Tc = the lower temperature (430)
Make sure to convert to Kelvin before using these temperatures.
(b) You would use the equation for efficiency again, but using work.
e = output work/input work
In this case input work would be 1.3 x 10^5 J, and your efficiency is 42%.
0.42 = output work/(1.3 x 10^5)
output work = 54600 J
Once you have the output work, you use it to calculate power.
P = W/t
Since it is already using energy per second your answer is the same as the output work. 54600 kW