Answer:
Explanation:
R=4x+3
H=3x+6
Volume of a cylinder= Πr²h
inserting the parameters
v=π(4x+3)²(3x+6)
v=π(16x²+24x+9)(3x+6)
V=π[3x(16x²+24x+9) +6(16x²+24x+9)]
v=Π(48x³+72x²+27x+96x²+144x+54)
v=π(48x³+168x²+171x+54)m³
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