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The water works commission needs to know the mean household usage of water by the residents of a small town in gallons per day. They would like the estimate to have a maximum error of 0.15 gallons. A previous study found that for an average family the standard deviation is 2.3 gallons and the mean is 17.6 gallons per day. If they are using a 80% level of confidence, how large of a sample is required to estimate the mean usage of water? Round your answer up to the next integer.

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7 votes

Answer: 387

Explanation:

Given : Standard deviation:
\sigma=2.3

Margin of error : 0.15

Critical value for 80% confidence interval = 1.2816

Required minimum sample size :
n=((z_(\alpha/2)\cdot \sigma)/(E))^2


\\\\=((1.2816*2.3)/(0.15))^2\\\\=386.16966144\approx387

Hence, the minimum sample size required to estimate the mean usage of water = 387

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