Question

The nuclear equation is incomplete. Superscript 239 Subscript 94 Baseline P u + Superscript 1 Subscript 0 Baseline n yields Superscript 100 Subscript 40 Baseline Z r + blank + 2 Superscript 1 Subscript 0 Baseline n What particle completes the equation?

Answer 1

Its A

Step-by-step explanation:

edg 2020

Answer 2

The particle which completes the given equation is :
`_(54)^(138)\textrm{Xe}`

Step-by-step explanation:

The given reaction is of a fission reaction:

`_(94)^(239)\textrm{Pu}+_0^1\textrm{n}\rightarrow _(40)^(100)\textrm{Zr}+_Z^A\textrm{X}+2_0^1\textrm{n}`

Total mass on the reactant side is equal to the total mass on the product side:

239 + 1 = 100 +A+ 2

A = 138

Sum of atomic numbers on the reactant side is equal to the sum of atomic number on the product side:

94 + 1(0) = 40 + Z + 2(0)

Z = 54

So atomic number 54 id of Xenon.

The particle which completes the given equation is :

`_(94)^(239)\textrm{Pu}+_0^1\textrm{n}\rightarrow _(40)^(100)\textrm{Zr}+_(54)^(138)\textrm{Xe}+2_0^1\textrm{n}`