Question

You place a box weighing 253.1 N on an inclined plane that makes a 39.7◦ angle with the horizontal.

Compute the component of the gravitational force acting down the inclined plane.
Answer in units of N.

Answer 1

The component of the gravitational force acting down the inclined plane can be calculated using the formula w = mg*sin(θ). In this case, the component is 157.7 N.

Step-by-step explanation:

The component of the gravitational force acting down the inclined plane can be calculated using the formula:

w = mg*sin(θ)

where w is the component of the weight parallel to the plane, m is the mass of the object, g is the acceleration due to gravity, and θ is the angle the inclined plane makes with the horizontal.

In this case, the weight of the box is given as 253.1 N. The mass can be calculated using the formula:

m = w/g

Plugging in the values:

m = 253.1 N / 9.8 m/s^2 = 25.8 kg

Now, we can calculate the component of the weight:

w = (25.8 kg) * 9.8 m/s^2 * sin(39.7°) = 157.7 N

So, the component of the gravitational force acting down the inclined plane is 157.7 N.

Answer 2

Step-by-step explanation:

The weight of the box is

W = 253.1N

Weight is on an incline plane

θ = 39.7°

The weight of an object is always acting downward

So, the weight makes an angle of 39.7° with the vertical component

Then, it's horizontal component is

Wx = W•Sinθ

Wx = 253.1 × Sin 39.7°

Wx = 161.67 N

The horizontal component of the weight is 161.67N

This is the force acting down the plane.

Check attachment