Question

What is the 4th term of the geometric sequence with
`a_(1)` = 5 and ratio (multiplier) = -3?

Answer 1

The 4th term of the geometric sequence with = 5 and ratio (multiplier) = -3 is -135

Solution:

Given that, first term a of a G.P = 5 and common ratio ( r ) = -3 for an geometric progression.

We have to find the 4th term of the above given geometric progression

We know that, nth term of an G.P is given by

`t_(n)=a \cdot r^(n-1)`

So, now, 4th term is

`\begin{aligned} t_(4) &=5 *(-3)^(4-1) \\ t_(4) &=5 *(-3)^(3) \\ t_(4) &=5 *(-27) \end{aligned}`

`t_(4)=-135`

hence, the 4th term of the given G.P is -135