Question

93.2 mL of a 2.03 M potassium fluoride (KF) solution is diluted with 3.92 L of water.

What will be the molarity of the diluted solution?


? M KF

EDIT: The answer is 0.047

Answer 1

0.047 M

Step-by-step explanation:

Given data:

Volume of KF = 93.2 mL

Molarity of KF = 2.03 M

volume of water added= 3.92 L

Solution:

First of all we will calculate the number of moles of KF.

number of moles = Molarity × volume in litter

number of moles = 2.03 mol/L × 0.0932 L

number of moles = 0.189 mol

Molarity of solution:

Total volume = 3.92 L + 0.0932 L = 4.0132 L

Molarity = number of moles / volume in litter

Molarity = 0.189 mol/ 4.0132 L

Molarity = 0.047 M