Question

What is the equation of the line that passes through the point (-4,2)(−4,2) and has a slope of -1−1?

Answer 1

`(\stackrel{x_1}{-4}~,~\stackrel{y_1}{2})\hspace{10em} \stackrel{slope}{m} ~=~ - 1 \\\\\\ \begin{array}c \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{- 1}(x-\stackrel{x_1}{(-4)}) \\\\\\ y-1=-1(x+4)\implies y-1=-x-4\implies y=-x-3`