Question

A constant driving force is applied to the car for the first 6 sec.at time t=16 sec the driver realises the car is travelling too fast for the 22 m s-1 speed limit (50 miles per hour and applies the break until time t=18 s.

a. Calculate the acceleration at time t=3sec

Answer 1

`2.17 m/s^2`

Step-by-step explanation:

The car accelerates at a constant rate during the first 6 seconds of the trip, so we can calculate its acceleration by using the equation:

`a=(v-u)/(t)`

where

v is the final velocity

u is the initial velocity

t is the time

For the first 6 seconds of the trip, we have: (from the graph)

v = 27 m/s

u = 14 m/s

t = 6 s

Substituting into the equation, we find:

`a=(27-14)/(6)=2.17 m/s^2`