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2 votes
Which complex number has a distance of 17 from the origin on the complex plane?

2+15i

17 + 1

020-31

4 - 1

Mark this and retum

User Jwrush
by
8.3k points

1 Answer

3 votes

Answer:

None of the options are correct.

Explanation:

Let the complex number is a + ib

Given distance from origin = 17 units

Now, by distance formula distance of a point from the origin =


17 = \sqrt{(x)^(2)  + (y)^(2) }

1) Check for 2 + 15 i

here,
√(15^2  +  2^2)  = √(225 + 4) = √(229) ≠ 17

2) Check for 17 + i

here,
√(17^2  +  1^2)  = √(289 + 1) = √(290)≠ 17

3) Check for 20 - 3 i

here,
√(20^2  +  (-3)^2)  = √(400 + 9) = √(409)≠ 17

4) Check for 4 - i

here,
√(4^2 &nbsp;+ &nbsp;(-1)^2) &nbsp;= √(16 + 1) = <strong>√(17) ≠ 17

Hence, none of the options are correct.

User Farhad Maleki
by
8.5k points

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