Question

An eagle carrying a trout flies above a lake along a horizontal path. The eagle drops the trout from a height of 6.1 m. The fish travels 7.9 m horizontally before hitting the water.

What is the velocity of the eagle? Round at the end of the calculation to the nearest tenth.

Answer 1

Answer: 7.1 m/s

Step-by-step explanation:

Answer 2

7.1 m/s

Step-by-step explanation:

The fish goes 6.1 m vrtically....calc the time to fall this far

d = 1/2 a t^2

6.1 = 1/2 ( 9.81)(t^2) shows t = 1.12 sec

It flies 7.9 m in 1.12 sec = 7.9/1.12 = 7.1 m/s