Question

Draw a fbd for a block at rest on a incline

Draw a fbd for a block at rest with a incline

Answer 1

Find the diagram in attachment

Step-by-step explanation:

In this problem we have a block at rest on the incline. There are only three forces acting on the block:

- The weight of the block, labelled as (mg), acting downward (where m = mass of the block and g = acceleration of gravity)

- The normal reaction exerted by the incline on the block, R, directed perpendicular to the plane

- The frictional force,
`F_f`, acting up along the plane

It is possible to resolve the forces along the two directions - parallel and perpendicular to the plane. We find the following equations of motion:

- Parallel direction:
`mg sin \theta - F_f = 0`

- Perpendicular direction:
`R - mg cos \theta = 0`

where
`\theta` is the angle of the inclined plane.