Question

4. Write the equation of the line that is parallel to the line y=-3x+4 that goes

through the point (9,-6).

Answer 1

Y =
`(X)/(3) - 9`

Explanation:

Given equation of first line as

Y = -3X + 4

Slop of the first line (m1) = -3

As first line is parallel to second line , then (m1) × (m2) = - 1

i.e m2 =
`(-1)/(m1)`

m2 =
`(-1)/(-3)`

m2 =
`(1)/(3)`

Now equation of seconf line with points (9 , -6) and slop
`(1)/(3)`

i.e equation of new line Y - y1 = m2 (X - x1)

Y + 6=
`(1)/(3)`

Y =
`(X)/(3) - (9)/(3) - 6`

Hence equation of new line is

Y =
`(X)/(3) - 9` Answer